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The resistance of a potentiometer wire ...

The resistance of a potentiometer wire is `10 Omega` and its length is 10m. A resistance box and 2V accumulator are placed in series with it. The value of resistance in the resistance box, if it is desired to have potential drop of 1 microvolt/mm is

A

`1990Omega`

B

`1890Omega`

C

`1190Omega`

D

`2290Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`(V)/(L)=I rho=((E)/(R+R_(h)))(R)/(L)`
`:.R+R_(h)=(2xx1)/(10^(-8))=2000 " " :.R_(h)=1990 Omega`
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