Current supplied by the cell in the adjoining figure is

Options

A. 1.5 A
B. `1 A`
C. `0.1A`
D. `0.5A`

Answer

C

Explanation

`I=(E)/(R+r)`
Where R is total external resistance `= 20 Omega`.
`:.R=(2)/(20+0)=(1)/(10)=0.1A`