Home
Class 12
PHYSICS
A light bulb is rated at 100 W for a 220...

A light bulb is rated at 100 W for a 220 V ac supply . The resistance of the bulb is

A

`200Omega`

B

`100Omega`

C

`484Omega`

D

`450Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`R=(V^(2))/(P)=(220xx220)/(100)=484 Omega`
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NIKITA PUBLICATION|Exercise Multiple Choice Questions|314 Videos

  • COMMUNICATION SYSTEMS

    NIKITA PUBLICATION|Exercise Multiple Choice Questions (Examples for Practice)|8 Videos

  • ELASTICITY

    NIKITA PUBLICATION|Exercise MCQ|314 Videos

Similar Questions

Explore conceptually related problems

A light bulb is rated at 100 W for a 220 V supply. Find (a) the resistance of the bulb. (b) the peak voltage of the source (c ) the rms current through the bulb.

A light bulb is rated 100W for a 220V supply. The resistance of the bulb and the peak voltage of the source respectively are

(a) For a given a.c., i = i_(m) sin wt, show that the average power dissipated in a resistor R over a complete cycle is (1)/(2) i._(m)^(2) R . (b) A light bulb is rated at 100 W for a 220 V a.c. supply. Calculate the resistance of the bulb.

A light bulb is rated 200 W for 220 V supply at 50 Hz. Calculate resistance of the bulb and rms current through the bulb.

A light bulb is rated 100 W for 220 V ac supply of 50 Hz. Calculate (i) the resistance of the bulb, (ii) the rms current through the bulb.

A light bulb is rated 150 W for 220 V ac supply of 60 Hz. Calculate (i) the resistance of the bulb, (ii) the rms current through the bulb.

For a light bulb rated at 110 W for a 200 V supply calculate its resistance and peak voltage of the source. Also calculate the runs current through the bulb.

An electric bulb is rated 60 W , 220 V . The resistance of its filament is

[" -) A light bulb is rated "100W" for "220V" ac supply of "50Hz" .Calculate "],[" i) the resistance of the bulb."],[" ii) the rms current through the bulb "]

NIKITA PUBLICATION-CURRENT ELECTRICITY-Multiple Choice Questions
  1. Current supplied by the cell in the adjoining figure is

    Text Solution

    |

  2. A wire of resistance 4 Omega is stretched to four times of its origina...

    Text Solution

    |

  3. A light bulb is rated at 100 W for a 220 V ac supply . The resistance ...

    Text Solution

    |

  4. In the circuit shown in figure, the value of R is

    Text Solution

    |

  5. When length of wire is increased by 10% , then increase in resistance ...

    Text Solution

    |

  6. For two wires, length ratio is 1:4, radius ratio is 1:2, specific resi...

    Text Solution

    |

  7. In potentiometer experiment, a cell is balanced by length 120cm. When ...

    Text Solution

    |

  8. S.I. unit of specific resistance is

    Text Solution

    |

  9. Four resistances arranged to form a Wheatstone's network are 8Omega, 1...

    Text Solution

    |

  10. When galvanometer of unknown resistance connected across a series comb...

    Text Solution

    |

  11. A potentiometer wire has a resistivity of 10^(9)Omega cm and area of c...

    Text Solution

    |

  12. In Wheatstone bridge, the resistances in four arms are 10Omega,10Omega...

    Text Solution

    |

  13. A wire has a resistance R. Find new resistance, (i) if radius of cro...

    Text Solution

    |

  14. Specific resistance of a metal conductor is 4xx10^(-5)Omegam and its a...

    Text Solution

    |

  15. A wire of length 1.6m has a resistance 8 Omega is connected to a batte...

    Text Solution

    |

  16. Sensitivity of potentiometer can be increased by

    Text Solution

    |

  17. S.I. unit of potential gradient is

    Text Solution

    |

  18. Kirchhoff's first rule obeys law of conservation of charge. Explain.

    Text Solution

    |

  19. The unit of specific resistance is

    Text Solution

    |

  20. Four resistances of 16 Omega , 12 Omega , 4 Omega and 9 Omega respecti...

    Text Solution

    |