In the circuit shown in figure, the value of R is

Options

A. `1Omega`
B. `2Omega`
C. `3Omega`
D. `4Omega`

Answer

B

Explanation

`R_(1)=1Omega, R_(2)=2 Omega, R_(3)=Romega, I_(1)=6 A, I_(2)=2A, R=?`
From figure, `I_(3)=11-8=3A`
Now in figure` R_(1), R_(2)` and `R_(3)` are in parallel.
`:.V=I_(1)R_(1)=I_(3)R_(3)`
`:.R_(3)=(I_(1)R_(1))/(I_(3))=(6xx1)/(3)`
`R_(3)=R=2Omega`