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A wire of resistance 4 Omega is stretche...

A wire of resistance `4 Omega` is stretched to twice its original length. The resistance of stretched wire would be

A

`4Omega`

B

`8Omega`

C

`16Omega`

D

`2Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`(R_(2))/(R_(1))=((l_(2))/(l_(1)))^(2)`
`R_(2)=((2l_(1))/(l_(1)))^(2)R_(1)=4xx4=16Omega`.
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