The resistance of the four arms P, Q, R ...

The resistance of the four arms `P, Q, R` and `S` in a Wheatstone's bridge are `10 ohm 30 ohm` and `90 ohm` rerspectively. The e.m.f. and internal resistance of the cell are `7 volt` and `5 ohm` respectively. If the galvanometer resistance is `50 ohm`, the current drawn for the cell will be

0.2A

0.1A

`2.0A`

`1.0A`

Text Solution

Verified by Experts

The correct Answer is:

`E=IR_(T)`
`I=(E)/(R_(T))=(7)/(5+(40xx120)/(40+120))`
`=0.2A`.

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