A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will be

Options

A. `2.00m`
B. `2.25m`
C. `2.50m`
D. `2.75m`

Answer

D

Explanation

`E_(1)=(V)/(L)xxl_(1):.l_(1)=(E_(1)L)/(V)` i.e., `l_(1)oo L`
`:.(l_(2))/(l_(1))=(L_(2))/(L_(1))`
i.e., `l_(2)=(11xx2.5)/(10)=2.75m`.