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The expression for magnetic induction in...

The expression for magnetic induction inside a solenoid of length `L` carrying a current `I` and having `N` number of turns is

A

`(mu_0)/(4pi)(N)/(L)1`

B

`mu NIL`

C

`(mu_0)/(4pi)NIL`

D

`mu_0(NI)/(L)`

Text Solution

Verified by Experts

The correct Answer is:
D
`B=mu_0nI=(mu_0NI)/(L) because n=(N)/(L)`
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