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If number of turns in moving coil galvan...

If number of turns in moving coil galvanometer becomes half , then the deflection for the same current will become

A

half

B

same

C

double

D

4 times

Text Solution

Verified by Experts

The correct Answer is:
A

`I prop theta thetefore I = K theta`
and `I_g prop theta' therefore I_g= Ktheta'`
`therefore (I_g)/(I)=(theta)/(theta)` But `I_(g)=((S)/(S+G))I`
`therefore (((S)/(S+G))I)/(I)=(theta)/(theta)therefore (S)/(S+G)=(theta)/(theta)`
`therefore (40)/(40+G)=(theta)/(2theta) therefore G=40 Omega`
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