If number of turns in moving coil galvanometer becomes half , then the deflection for the same current will become
A
half
B
same
C
double
D
4 times
Text Solution
Verified by Experts
The correct Answer is:
A
`I prop theta thetefore I = K theta` and `I_g prop theta' therefore I_g= Ktheta'` `therefore (I_g)/(I)=(theta)/(theta)` But `I_(g)=((S)/(S+G))I` `therefore (((S)/(S+G))I)/(I)=(theta)/(theta)therefore (S)/(S+G)=(theta)/(theta)` `therefore (40)/(40+G)=(theta)/(2theta) therefore G=40 Omega`
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