The deflection in a M.C.G. is reduced to half , when it is shunted with a `40 Omega` coil. The resistance of the galvanometer is
A
`60Omega`
B
`40Omega`
C
`20Omega`
D
`10Omega`
Text Solution
Verified by Experts
The correct Answer is:
B
From problem (67),we have , `(S)/(S+G)=(theta)/(theta) therefore (12+G)/(12)=(50)/(10)` `therefore G=48Omega`.
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