The M.C.G. has resistance G and `I_g` be the minimum current for it full scale deflection. To convert M.C.G.into ammeter of range. IA, the required shunt is
A
`S=((l_g)/(1-l_g))G`
B
`S-((I_g-G)/(I))`
C
`S=(I_g)/(G(I-I_g))`
D
none of these
Text Solution
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The correct Answer is:
A
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