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When a galvanometer of resistance G iws ...

When a galvanometer of resistance G iws converted into an ammeter of range IA then the current passing through shunt (S) is

A

`I_s=((G)/(G+S))I`

B

`I_s=((S)/(S+G))I`

C

`I_s=((SI-G)/(S))`

D

`I_s=SxxG`

Text Solution

Verified by Experts

The correct Answer is:
A
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