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A galvanometer of resistance 100Omega gi...

A galvanometer of resistance `100Omega` gives full deffection for a current `10^(-5)` the value of shunt required to convert it into ammeter of range 1 ampere is:-

A

`10^-3Omega` in series

B

`100Omega` in parallel

C

`100 Omega` in series

D

`10^-3` in parallel

Text Solution

Verified by Experts

The correct Answer is:
D
`I=((S+G)/(S))l_(g)=((2+40)/(2))xx0.01=0.21A`
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