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If galvanometer is shunted by 1//n^(th) ...

If galvanometer is shunted by `1//n^(th)` of its value, then what fraction of the current passes through the galvanometer ?

A

`1//n`

B

`n`

C

`1//(n+1)`

D

`1//(n-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`V_g=I_g G therefore G=V_g//I_g=50Omega`
`S=((I_g)/(I-I_g))G=((0.015)/(25-0.015))xx50=0.03Omega`
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