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An ammeter has a resistance of 100 Omega...

An ammeter has a resistance of `100 Omega A` potential difference of 50 m V between its terminals gives full scale deflection. How will you convert it into an ammeter of range 5A ?

A

`0.01 Omega`

B

`0.1Omega`

C

`1 Omega`

D

`10 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
The combined resistance of galvanometer and its shutn is ,
`R_A=(SG)/(S+G) therefore 25=(500xxS)/(500+S)`
`therefore S=26.3Omega`
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