Resistance of galvanometer is `500Omega`. Effective resistance of ammeter with shunt is `25 Omega`. What is the value of shunt ?
A
`25 Omega`
B
`50 Omega`
C
`23.6 Omega`
D
`26.3Omega`
Text Solution
Verified by Experts
The correct Answer is:
D
`I_s((G)/(S+G))I=((48)/(2+48))I=((48)/(50))I` Thus , `96%` of total current will pass through shunt of resistance of `2Omega`.
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