A galvanometer has a resistance `G Omega`. It is shunted by a resistance of `S Omega`. How much resistance should be added in series so that the main current in the curcuit remains unchanged ?
A
`(S)/(S+G)`
B
`(G)/(G+S)`
C
`(G^2)/(G+S)`
D
`(SG)/(G+S)`
Text Solution
Verified by Experts
The correct Answer is:
C
As range of ammeter increases the value of shunt decreases.
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