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A galvanometer of resistance 40 Omega gi...

A galvanometer of resistance `40 Omega` gives the full scale deflection for a current of 10 m A through it. A resistance of `9960Omega` is connected in series with the galvanometer coil. The mximum voltage that can be measured by the voltmeter is

A

10 V

B

100 V

C

50 V

D

500 V

Text Solution

Verified by Experts

The correct Answer is:
B
`V=I_g(R+G)`
`=10xx10^-3(9960+40)=100V`.
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Knowledge Check

  • A galvanometer of resistance 100 Omega gives the full scale deflection for a current of 10 m A. If a resistance of 1 Omega is connected in parallel to the coil of the galvanometer , then maximum current that can be measured with the galvanometer will be

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