A galvanometer of resistance `40 Omega` gives the full scale deflection for a current of 10 m A through it. A resistance of `9960Omega` is connected in series with the galvanometer coil. The mximum voltage that can be measured by the voltmeter is
A
10 V
B
100 V
C
50 V
D
500 V
Text Solution
Verified by Experts
The correct Answer is:
B
`V=I_g(R+G)` `=10xx10^-3(9960+40)=100V`.
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