A voltmeter has a resistance of `100 Omega` and measures 10 V. How can it be used to meaure 50 V ?
A
`40 Omega` in series
B
`40 Omega` in parallel
C
`400 Omega` in series
D
`400 Omega` in parlllel
Text Solution
Verified by Experts
The correct Answer is:
C
`R=G(n-1)=100(5-1)` `=400Omega` in series.
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