What is the relation between voltage sensitivity `S_(v)` and the current sensitivity S of a moving coil galvanometer ? (Given that G is the resistance of the galvanometer.)
A
`S_v = GS`
B
`S_v=(S_i)/(G)`
C
`S_v S_i = G`
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
B
`S_i=(n AB)/(K) and S_v=(n AB)/(KG)` `therefore S_v=(S_i)/(G)`.
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