One proton beam enters a magnetic field of `10^(-4) T` normally. Specific charge `=10^(11)C//kg`. Velocity `=10^(7)m//s`. What is the radius of the circle described by it
A
0.1 m
B
1 m
C
10 m
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
`r=(mv)/(q B) =(10^2)/(10^11xx10^-4)=1m`
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