Home
Class 12
PHYSICS
A proton of energy 8 eV is moving in a c...

A proton of energy `8 eV` is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be

A

4eV

B

2eV

C

8eV

D

6eV

Text Solution

Verified by Experts

The correct Answer is:
C
`E=(q^2B^2r^2)/(2m)`
`therefore (E_alpha)/(E_P)=((q_alpha)/(q_P))^2 (m_p)/(m_alpha)=(4)/(1)xx(1)/(4)`
`therefore E_alpha=E_p=8eV`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    NIKITA PUBLICATION|Exercise MCQs (Sensitivity and accuracy of M.C.G.)|1 Videos

  • KINETIC THEORY OF GASES & RADIATION

    NIKITA PUBLICATION|Exercise MCQs (Question Given in MHT-CET)|79 Videos

  • MAGNETISM

    NIKITA PUBLICATION|Exercise MCQs|249 Videos

Similar Questions

Explore conceptually related problems

A proton of energy E is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be equal to

A charged particle is moving in a circular path in uniform magnetic field. Match the following.

The energy of a charged particle moving in uniform magnetic field does not change-Explain.

The path of a charged particle moving in a uniform steady magnetic field cannot be a

A particle is moving in a uniform magnetic field, then

A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in unifrom magentic field. What should be the energy of an alpha- particle to describe a circle of the same radius in the same field?

A charged particle moves in a uniform magnetic field. The velocity of the particle at some instant makes an acute angle with the magnetic field. The path of the particle will be

A charged particle moves in a uniform magnetic field. The velocity of the particle at some instant makes an acute angle with the magnetic field. The path of the particle will be