What is cyclotron frequency of an electron with an energy of 100 eV in the earth's magnetic field of `1xx10^(-4)Wb//m^(2)` if its velocity is perpedicular to magnetic field.
A
0.7 MHz
B
2.8 MHz
C
1.4 MHz
D
2.1 MHz
Text Solution
Verified by Experts
The correct Answer is:
B
`E_(k) =100 e V, B=1 xx10^-4 T, v =? Q=e` `v=(q B)/(2 pi m)` `=(1.6xx10^-19xx1xx10^-4)/(2xx3.14xx9.1xx10^-31)=2.8MHz`
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