A proton is to circulate the earth along the equator with a speed of `1.0 xx 10^(7)` m/s. The minimum magnetic field which should be created at the equator for this purpose. (The mass of proton `=1.7 xx 10^(-27)` kg and radius of earth `= 6.37 xx 10^(6)` m.) will be (in `"Wb/m"^(2)`)
A
`1.6xx10^-27 kg `
B
`2.6 xx10^-8 T`
C
`3.6xx10^-8 T`
D
`4.6xx10^-8 T`
Text Solution
Verified by Experts
The correct Answer is:
A
For circular motion the required centripetal force is provided by magnetic force. i.e., ` q v B=(m v^2)/(r) therefore B=(mv)/(qr)` `B=1.6xx10^-8 T`.
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