A long straight wire carries a current of 50 A. An electron moving at `10^(7)` m/s is 5 cm away from the wire. The force acting on electron if its velocity is directed towards the wire will be
A
`1.6xx10^-16N`
B
`3.1xx10^-16 N`
C
`4.8xx10^-16N`
D
`1.8xx10^-16N`
Text Solution
Verified by Experts
The correct Answer is:
B
`B=(mu_0I)/(2pi a)` `F=q v B sin theta , theta =90^@` `F=q v B = ev B` `=e V (mu_0I)/(2 pi a)` ` =3.2 xx 10^-16 N`.
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