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A long straight wire carries a current of 50 A. An electron moving at `10^(7)` m/s is 5 cm away from the wire. The force acting on electron if its velocity is directed towards the wire will be

A

`1.6xx10^-16N`

B

`3.1xx10^-16 N`

C

`4.8xx10^-16N`

D

`1.8xx10^-16N`

Text Solution

Verified by Experts

The correct Answer is:
B

`B=(mu_0I)/(2pi a)`
`F=q v B sin theta , theta =90^@`
`F=q v B = ev B`
`=e V (mu_0I)/(2 pi a)`
` =3.2 xx 10^-16 N`.
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