In Bohr model of hydrogen atom , the electron `0.5Å` at a frequency of `6.8 xx10^15` rev/s. The magnetic field at the centre and magnetic moment will be
A
`14T,9xx10^-24Am^2`
B
`7T,9xx10^-24Am^2`
C
`14T,7xx10^-24Am^2`
D
`7T,14xx10^-24Am^2`
Text Solution
Verified by Experts
The correct Answer is:
A
`B=(mu_0I)/(2 pi a) (I=(q)/(T)=ef)` `B=(mu_0 ef)/(2a) =14 T` `M=n I A , n=1, A = pi r^2` `=9xx10^-24 Am^2`.
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