A conductor of length 1m and carrying current of 1A is placed at an angle `45^@` to the magnetic field of 1 oersted. The force acting on the conductor is
A
`(10^-4)/(sqrt(2))N`
B
`(10^-4)/(sqrt(3))N`
C
`(10^-2)/(sqrt(3))N`
D
`(10^-2)/(sqrt(2))N`
Text Solution
Verified by Experts
The correct Answer is:
A
`F=I b l sin theta = (10^-4)/(sqrt(2))N`.
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