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A wire of length l carries a steady curr...

A wire of length l carries a steady current. It is bent first to form a circular plane loop of one turn. The magnetic field at the centre of the loop is B. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same is

A

B

B

2B

C

3B

D

4B

Text Solution

Verified by Experts

The correct Answer is:
D

`B_1=B=(mu_0 n_1 I)/(2r_1)=B`
When same length is bent into 2 turns radius of coil is halved
`B_2=(mu_0 n_2 I)/(2 r_2)=4(mu_0 I)/(2 r) = 4B`
`(B_2)/(B_1)=(4B)/(B)=(4)/(1)`
`B_2=4B_1=4B`.
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