Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii `R_1 and R_2,` respectively. The ratio of masses of X and Y is
A
`((R_1)/(R_2))^2`
B
`((R_2)/(R_1))^2`
C
`(R_2)/(R_1)`
D
`(R_1)/(R_2)`
Text Solution
Verified by Experts
The correct Answer is:
A
`R=(mv)/(q B)=(sqrt(2mqV))/(q B)=(1)/(B) (sqrt(2mV))/(q)` For same charge and potential difference , `Rprop sqrt(m)rArr (R_1)/(R_2)=sqrt((m_1)/(m_2)` `therefore (m_1)/(m_2)=((R_1)/(R_2))^2` .
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