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A 2MeV proton is moving perpendicular to...

A `2MeV` proton is moving perpendicular to a uniform magnetic field `2.5` tesla. The force on the proton is

A

`8xx10^-10N`

B

`4xx10^-10N`

C

`6xx10^-10N`

D

`8xx10^-12N`

Text Solution

Verified by Experts

The correct Answer is:
D

`E_k=(1)/(2)mv^2{v=2xx10^7 m//s)`.
`F=qv Bsin 90 =8xx10^-12N`.
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