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A particle of charge q and mass m moves ...

A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

A

`q//m`

B

`2q//m`

C

`q//2m`

D

`q^2//2m`

Text Solution

Verified by Experts

The correct Answer is:
C
Magnetic moment is given by , `M=IA=(q)/(T) pi r^2=(2pi)/(T)(qr^2)/(2)=(omega qr^2)/(2)`
Angular momentum `=L=I omega=mr^2omega`
`therefore (M)/(L)=(omegaq r^2//2)/(mr^2omega)=(q)/(2m)`.
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