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A galvonometer of resistance 20 Omega g...

A galvonometer of resistance `20 Omega` gives a full scale deflection with a current of 0.04A is passed through it. It is derised to convert it into an ammeter of range 20A . The only shunt available is `0.05 Omega` . The resistance that must be converted in series with the coil of the galvonometer is

A

`2.95 Omega`

B

`4.95 Omega`

C

`4.35 Omega`

D

`4.25Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
In parallel combination potential is same
`therefore I_g (G+R)=(I-I_g)S`
`0.04(20+R)=(20-0.04)0.05`
`therefore R=4.95Omega` .
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