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When a battery of emf 2 V is directly co...

When a battery of emf 2 V is directly connected to a galvanometer of resistance `100 Omega`. It shows full scale deflection. To measure 1 A current , the shunt must be

A

`(49)/(10)Omega`

B

`(10)/(49)Omega`

C

`(100)/(49)Omega`

D

`(49)/(100)Omega`

Text Solution

Verified by Experts

The correct Answer is:
C

For same current , Initial resistance = Final resistance of circuit
i.e., `G=(G.S)/(G+S)+R therefore R=(G^2)/(G+S)`.
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