A voltmeter reading upto 10 V has a resistance of`1000 Omega`. It can be converted into an ammeter reading up ot 10 A by connecting a shunt of
A
`1Omega`
B
`0.1Omega`
C
`2Omega`
D
`0.2Omega`
Text Solution
Verified by Experts
The correct Answer is:
A
`I_g =(V)/(R_v)=(10)/(1000)=(1)/(100)A` here `R_v=G` `therefore` Required shunt, `S=((I_g)/(I-I_g)).G=1 Omega`
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