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A galvanometer having a resistance of 75...

A galvanometer having a resistance of `75 Omega` gives the full scale deflection for the current of 25mA. The shunt required to convert it into an ammeter to measure the current up to 59 A is

A

`0.017Omega`

B

`0.047Omega`

C

`0.027Omega`

D

`0.031Omega`

Text Solution

Verified by Experts

The correct Answer is:
D

`S=((I_g)/(I-I_g))G=(25xx10^-3)/((50-0.025))xx75=0.0375 Omega`
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