The combined resistance of a galvanometer of resistance of `495` ohm and its shunt is `9.9 Omega` . The shunt resistance is
A
`1.01Omega`
B
`8.9Omega`
C
`10.1Omega`
D
`9.1Omega`
Text Solution
Verified by Experts
The correct Answer is:
C
`R_A =(GS)/(S+G)` `9.9 S +495xx9.9 = 495 S S =(495xx9.9)/(485.1)=10.1Omega `.
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