A galvanometer of resistance `100Omega` gives full scale deflection for the current of 0.1 A . The series resistance required to convert it into voltmeter of range 100 V is
A
`800Omega`
B
`900Omega`
C
`700Omega`
D
`600Omega`
Text Solution
Verified by Experts
The correct Answer is:
B
`R=(V)/(I_g)-G=(100)/(0.1)-100=900Omega` .
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