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A galvanometer has current range 0 to 25...

A galvanometer has current range 0 to 25 m A and voltage range 0 to 500mV. How will you adopt it to read the potential difference up to 10 V ?

A

`480Omega`

B

`280Omega`

C

`830Omega`

D

`380Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
(i) `V=I_g G G=(500xx10^-3)/(2.5xx10^-3)=20Omega`
(ii) `R=(V)/(I_g)-G=(10)/(25xx10^-3)-20=400 -20=380Omega` .
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