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The current measuring capacity of a galv...

The current measuring capacity of a galvanometer of resistance `50 Omega` is to be increased from x mA to `101 xxmA`.The shunt resistance is

A

`0.5Omega`

B

`0.25Omega`

C

`1.5Omega`

D

`0.35Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`S=(G)/((n-1))=(50)/((101-1))=(50)/(100)=0.5Omega` .
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