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A galvanometer has a current sensitivity...

A galvanometer has a current sensitivity of 5 div/m A and a voltage sensitivity of 2 div/m V . If the instrument has 30 divisions. How will you use it to measure a current of 3A?

A

`0.001Omega`

B

`0.005Omega`

C

`0.002Omega`

D

`0.004Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
(i) `S_V=(S_i)/(G) G=(S_i)/(S_V)=(5)/(2)=2.5Omega`.
(ii) For 1m A , the deflection is 5 divisions. Thus , for 30 divisions , i.e., current requried for maximum deflection is 6 m A , i.e., `I_g`. Therefore,
`S=((I_g)/(I-I_g))G=(6xx10^-3)/((3-0.006))xx2.5=5mOmega`.
`=0.005Omega`.
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