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A galvanometer of resistance 100 Omega g...

A galvanometer of resistance `100 Omega` gives the full scale deflection for a current of 10 m A. If a resistance of `1 Omega` is connected in parallel to the coil of the galvanometer , then maximum current that can be measured with the galvanometer will be

A

1.01A

B

1.11A

C

10.1A

D

0.01A

Text Solution

Verified by Experts

The correct Answer is:
A
`S=((I_g)/(I-I_g))G`
`I-I_g=(10^-2xx10^2)/(1)=1 therefore I=1+0.01=1.01 A `
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