A cyclotron is operating at a frquency of `12xx10^6Hz`. Mass of deutron is `3.3 xx10^-19` coulomb. To accelerate deutrons the magnetic field is
A
0.016 tesla
B
0.16 tesla
C
16 tesla
D
1.6 tesla
Text Solution
Verified by Experts
The correct Answer is:
D
`v =(q B)/(2 pi m)` `therefore B =(2 pi mv )/(q)` `=(2xx3.14xx3.3 xx10^-27xx12xx10^6)/(1.6xx10^-19)` `= 1.6 T`.
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