A proton an an `alpha-`particle, moving with the same velocity, enter a uniform magnetic field, acting normal to the plane of their motion. The ratio of the radii of the circular paths descirbed by the proton and `alpha`-particle is
A
`1:1`
B
`1:2`
C
`1:4`
D
`2:1`
Text Solution
Verified by Experts
The correct Answer is:
B
`r=(mv)/(q B) therefore r prop (m)/(v)` `(r_1)/(r_2)=(m_rho)/(m_alpha)(q_alpha)/(qrho)` `therefore (R_1)/(R_2)=(m_p)/(4m_p) xx(2q_p)/(q_p)=(1)/(2)`
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