Home
Class 12
PHYSICS
To convert a 400 m V range galvanometer ...

To convert a 400 m V range galvanometer of resistance `20 Omega` into a ammeter of 100 m A ranges , the required shunt resistance to be connected is

A

`5Omega`

B

`4Omega`

C

`2.5Omega`

D

`1.5Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_g=(V_g)/(G)=(400)/(20)=20xx10^-3A =20 m A `
Now , `S=(I_g .G)/(I-I_g)`
`S=(20xx20)/(100-20)=(20xx20)/(80)=5 Omega` .
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    NIKITA PUBLICATION|Exercise MCQs (Sensitivity and accuracy of M.C.G.)|1 Videos

  • KINETIC THEORY OF GASES & RADIATION

    NIKITA PUBLICATION|Exercise MCQs (Question Given in MHT-CET)|79 Videos

  • MAGNETISM

    NIKITA PUBLICATION|Exercise MCQs|249 Videos

Similar Questions

Explore conceptually related problems

To convet a 800 mV range milli voltmeter of resistance 40 Omega into a galvanometer of 100 mA range, the resistance to be connected as shunt is

When a galvanometer of resistance G iws converted into an ammeter of range IA then the current passing through shunt (S) is

What is the value of shunt resistance required to convert a galvanometer of resistance 100 Omega into an ammeter of range 1A ? (Given : Full scale deflection of the galvanometer is 5 mA.)

A milliammeter of range 10 mA has a coli of resistance 1 Omega . To use it as an ammeter of range 1 A , the required shunt must have a resistance of

A voltmeter of range 3V and resistance 200Omega cannot be converted to an ammeter of range

A galvanometer of resistance 25Omega measures 10^(-3)A . shunt required to increase range up tow 2 A is

A voltmeter of 250 mV range having a resistance of 10 Omega is converted into an ammeter of 250 mA range. The value of necessary shunt is (nearly)

A voltmeter of range 3 V and resistance 200Omega connot be converted to an ammeter of range