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When a current of 318 m A is passed thro...

When a current of 318 m A is passed through a tangent galvanometer , a deflection of `45^@` is obtained. If radius of coil is 10 cm and number of turns 50 , then what is a value of horizontal component of earth's magnetic field ?

A

`10^-6 T`

B

`10^-7 T`

C

`10^-2 T`

D

`10^-4 T`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=318mA, theta=45^@,a=10cm,n=50,B_H=?`
For tangent galvanometer,
`I=(2aB_H)/(mu_0n)tan theta`
`therefore B_H = (mu_0 n I)/(2 a tan theta)`
`= (4 pi xx10^-7xx50xx318xx10^-3)/(2xx10xx10^-2xxtan 45)`
`= 10^-4 T` .
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