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In an ammeter, 4% of the main current is...

In an ammeter, 4% of the main current is passing through the galvanometer. If shunt resistance is 5 `Omega`, then resistance of galvanometer will be

A

`60Omega`

B

`120Omega`

C

`240Omega`

D

`480Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`(I_g)/(I)=4%,S=5Omega,G=?`
`(I_g)/(I)=(S)/(S+G)`
`(4)/(100)=(5)/(5+G)`
`(1)/(25)=(5)/(5+G)`
`5+G=125`
`G=120Omega `.
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