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The current sensitivity of a galvanomete...

The current sensitivity of a galvanometer is x div/m A and voltage sensitivity is y div/V . The resistance of galvanometer is G. Then relation between x and y is

A

`G=(x)/(y)xx10^3`

B

`G=(y)/(x)`

C

`G=(x)/(y)`

D

`y=Gxx10^3`

Text Solution

Verified by Experts

The correct Answer is:
A
`S_i=x " div"//mA,S_V=y" div"//V,G=?`
`S_V=(S_i)/(G)therefore G=(S_i)/(S_V)`
`therefore G=(x xx10^3)/(y)`
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