when a proton is released from rest in a room, it starts with an initital acceleration `a_0` towards west . When it is projected towards north with a speed `v_0,` it moves with an initial acceleration `3a_0` towards west. Find the elecrtic field and the minimum possible magnetic field in the room.
A
`(ma_0)/(2)"west",(2ma_0)/(ev_0)"down"`
B
`(ma_0)/(e)"east",(3ma_0)/(ev_0)"up"`
C
`(ma_0)/(e)"east",(3ma_0)/(ev_0)"down"`
D
`(ma_0)/(e)"west",(3ma_0)/(ev_0)"up"`
Text Solution
Verified by Experts
The correct Answer is:
A
`ma_0= eErArr E=(ma_0)/( e)` and `(e _0 B+ e E)/(m)=3a_0` `rArr ev_0B=3ma_0-e E =3ma_0 -ma_0=2ma_0` `rArr B=(2ma_0)/(ev_0)`.
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