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Magnetic induction produced at the centr...

Magnetic induction produced at the centre of a circular loop carrying current is B . The magnetic moment of the loop of radius R is
(Me = permeability of tree space)

A

`(BR^3)/(3pimu_0)`

B

`(2piBR^3)/(mu_0)`

C

`(BR^2)/(2pimu_0)`

D

`(2piBR^2)/(mu_0)`

Text Solution

Verified by Experts

The correct Answer is:
B
`B=(mu_0n I)/(2a)=(mu_0 nI)/(2a)xx(A)/(A)`
`B=(mu_0M)/(2axxpia^2)`
`therefore M=(2pi Ba^3)/(mu_0)`
i.e.,`M=(2pi BR^3)/(mu_0)`.
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