A short bar magnet has a magnetic moment of 10 `Am^(2)`.If its length is 10 cm,then the pole strength of the dipole is

Options

A. 200 Am
B. 100 Am
C. 150 Am
D. 50 Am

Explanation

To find the pole strength of the dipole, we can use the relationship between the magnetic moment (M), pole strength (P), and the distance between the poles (L) of a bar magnet. The formula is given by:

\[ M = P \times L \]

Where:
- \( M \) is the magnetic moment,
- \( P \) is the pole strength,
- \( L \) is the distance between the poles.

### Step-by-Step Solution:

1. **Identify the given values**:
- Magnetic moment \( M = 10 \, \text{Am}^2 \)
- Length of the magnet \( L = 10 \, \text{cm} \)

2. **Convert the length from centimeters to meters**:
- Since \( 1 \, \text{cm} = 0.01 \, \text{m} \),
- Therefore, \( L = 10 \, \text{cm} = 10 \times 0.01 \, \text{m} = 0.1 \, \text{m} \).

3. **Rearrange the formula to solve for pole strength \( P \)**:
- From the formula \( M = P \times L \), we can rearrange it to find \( P \):
\[ P = \frac{M}{L} \]

4. **Substitute the known values into the equation**:
- Now substitute \( M = 10 \, \text{Am}^2 \) and \( L = 0.1 \, \text{m} \):
\[ P = \frac{10 \, \text{Am}^2}{0.1 \, \text{m}} \]

5. **Calculate the pole strength**:
- Performing the division:
\[ P = 100 \, \text{A} \]

### Final Answer:
The pole strength of the dipole is \( 100 \, \text{A} \).